LeetCode 242 - 有效的字母异位词

class Solution:
    def isAnagram(self, s: str, t: str) -> bool:
        # 长度不同的情况直接退出
        if len(s) != len(t):
            return False
        sC = Counter(s)
        for i in t:
            if i not in sC:
                return False
            else:
                if sC[i] == 0:
                    return False
                else:
                    sC[i] -= 1
        sC += Counter()
        return True